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A ball of mass 0.150kg is dropped from a height of 1.25m. It rebounds from the floor to reach a height of 0.960m. What impulse was given to the ball by the floor?

  • PHYSICS - ,

    Calculate the downward velocity V1 when it hits the floor:
    V1 = sqrt (2gH), where H = 1.25 m
    Then calculate the upward velocity after the bounce:
    V2 = sqrt (2gH'), where H' = 0.96 m
    The momentum change is M(V1 + V2), since the V's are in opposite directions.
    The momentum change equals the impulse given by the floor.

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