This is an SAT question of the day that I can't understand.

The sum of the digits of a three-digit number is 12. If the hundreds digit is 3 times the tens digit and the tens digit is 1 over 2 the units digit, what is the tens digit of the number?
Answer choices:
2
3
4
6
9

I don't know what 1 over 2 the units digit means.

I don't know either. Could it just mean 1/2 more than the tens digit?

Let the digits be H, T and U

H + T + U = 12
H = 3T
T = (1/2) U
4T + 2T = 12
T = 2
T is the tens digit

To solve this question, we need to analyze the information given and find the tens digit of the three-digit number that satisfies the given conditions.

Let's break down the information provided:

1. The sum of the digits of the three-digit number is 12.
2. The hundreds digit is 3 times the tens digit.
3. The tens digit is 1 over 2 the units digit.

Let's assume the three-digit number is represented as "ABC," where A is the hundreds digit, B is the tens digit, and C is the units digit.

According to condition 1, we know that A + B + C = 12.

According to condition 2, we know that A = 3B.

According to condition 3, we know that B = 1/2C.

Now, let's substitute the values from conditions 2 and 3 into condition 1 to eliminate variables:

3B + B + 2B = 12
6B = 12
B = 2

Therefore, the tens digit of the number is 2.

So, the correct answer is 2.