Posted by Anonymous on Saturday, March 29, 2008 at 12:19pm.
The cross product is the vector that one can calculate with this determinant:
| i j k |
| 2-1 3 |
| 1 4-2 |
= (2-12) i + (3+4)j + (8+1) k
= -10i +7j +9k
or (-10, 7, 9) in your notation.
That vector, or any vector that is a scalar multiple of it, will be perpendicular to the other two vectors.
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