Math
posted by Anonymous on .
Use the cross product to find a vector perpendicular to each of the following pairs of vectors.
(2, 1, 3) and (1, 4, 2)
Can someone please explain this step by step?

The cross product is the vector that one can calculate with this determinant:
 i j k 
 21 3 
 1 42 
= (212) i + (3+4)j + (8+1) k
= 10i +7j +9k
or (10, 7, 9) in your notation.
That vector, or any vector that is a scalar multiple of it, will be perpendicular to the other two vectors.