Posted by **Anonymous** on Saturday, March 29, 2008 at 12:19pm.

Use the cross product to find a vector perpendicular to each of the following pairs of vectors.

(2, -1, 3) and (1, 4, -2)

Can someone please explain this step by step?

- Math -
**drwls**, Saturday, March 29, 2008 at 1:32pm
The cross product is the vector that one can calculate with this determinant:

| i j k |

| 2-1 3 |

| 1 4-2 |

= (2-12) i + (3+4)j + (8+1) k

= -10i +7j +9k

or (-10, 7, 9) in your notation.

That vector, or any vector that is a scalar multiple of it, will be perpendicular to the other two vectors.

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