A sample of hydrogen has a volume of 1100 mL when the temperature is -0.899999999999999 degC and the pressure is 0.888 atm. What will be the volume of the gas at STP?
PV=nRT solve for the number of moles, n.
Now multiply n by 22.4L to get the volume at STP.
To find the volume of the gas at STP (Standard Temperature and Pressure), we need to use the combined gas law:
PV/T = PV/T
Where:
P = pressure
V = volume
T = temperature
STP conditions are defined as 1 atmosphere of pressure and 0 degrees Celsius (or 273.15 Kelvin).
Let's convert the given temperature from degrees Celsius to Kelvin:
T (Kelvin) = T (Celsius) + 273.15
Given:
P1 = 0.888 atm (initial pressure)
V1 = 1100 mL (initial volume)
T1 = -0.899999999999999 degC (initial temperature)
P2 = 1 atm (STP pressure)
V2 = ? (STP volume)
T2 = 0 degC (STP temperature)
Now, let's plug in the values into the combined gas law equation:
(P1 x V1) / T1 = (P2 x V2) / T2
(0.888 atm x 1100 mL) / (-0.899999999999999 degC + 273.15) = (1 atm x V2) / (0 degC + 273.15)
(0.888 atm x 1100 mL x 273.15) / (-0.899999999999999 + 273.15) = (1 atm x V2 x 273.15) / 273.15
Now, solve this equation for V2 to find the volume of the gas at STP:
V2 = (0.888 atm x 1100 mL x 273.15) / (-0.899999999999999 + 273.15)
Calculating the above expression will give you the volume of the gas at STP.