Posted by G on .
I am trying to solve the sytems of equations using the elimination method.
I tied multiplying the first equation by 2 and the second by 4. Then I tried multiplying the first equation by -3 and the secondy by 3.
The book says the answers are 3,1.
I am not getting these answers.
Try to multiply first equation by 3 and second equation by 2. You will end up with 6x and -6x, you can eliminate those and then use the substitution method to find y.
Multiply the second equation by 2/3
add the equations
Put that y back into either equation, and solve for x.