posted by Sarah H on .
A liquid is heated from 33.96°C to 104.32°C. The vapor pressure increases from 23.54torr to 984.35torr. What is the heat of vaporization of the liquid in kJ/mol?
The change in temperature is 70.36°C.
Change in vapor pressure = 960.76 torr.
What is the equation to find the heat of vaporization given that we know the change in pressure, and change in temperature?
Isn't that the Clausius-Clapeyron equation?