March 30, 2017

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A liquid is heated from 33.96°C to 104.32°C. The vapor pressure increases from 23.54torr to 984.35torr. What is the heat of vaporization of the liquid in kJ/mol?

The change in temperature is 70.36°C.
Change in vapor pressure = 960.76 torr.

What is the equation to find the heat of vaporization given that we know the change in pressure, and change in temperature?

  • Gen Chem - ,

    Isn't that the Clausius-Clapeyron equation?

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