Algebra
posted by John .
Determine if the function is even, odd or neither.
f(x)=2x^5+2x^3
f^1x=2(x)^5+2(x)^3
f^1x=2x^5+2x^3
f^1x=2x^52x^3
f(x)=2x^5+2x^3
f^1x=2(x)^5+2(x)^3
f^1x=2x^5+2(x)^3
f^1x=(2x^5)+(2x^3)
f^1x=2x^52x^3
Not even. This function is odd.

that is f(x) you want but your answer is correct.
f(x) = 2(x)^5 + 2(x)^3
but (x)^5 =  x^5
and (x)^3 =  x^3
so
f(x) = 2 x^5  2 x^3
= f(x)
so odd because f(x) =  f(x))