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December 19, 2014

December 19, 2014

Posted by **John** on Friday, March 28, 2008 at 6:52pm.

f(x)=2x^5+2x^3

f^-1x=2(-x)^5+2(-x)^3

f^-1x=-2x^5+-2x^3

f^-1x=-2x^5-2x^3

f(x)=2x^5+2x^3

f^-1x=2(-x)^5+2(-x)^3

f^-1x=-2x^5+2(-x)^3

f^-1x=(-2x^5)+(-2x^3)

f^-1x=-2x^5-2x^3

Not even. This function is odd.

- Algebra -
**Damon**, Friday, March 28, 2008 at 6:58pmthat is f(-x) you want but your answer is correct.

f(-x) = 2(-x)^5 + 2(-x)^3

but (-x)^5 = - x^5

and (-x)^3 = - x^3

so

f(-x) = -2 x^5 - 2 x^3

= -f(x)

so odd because f(-x) = - f(x))

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