Does this relation define a function?
y |0|1| 2| 3
y^2=3x is a function because the coordinates I chose are not duplicated.
Algebra - Damon, Friday, March 28, 2008 at 6:07pm
y^2 = 3 x
y = + sqrt(3x)
y = - sqrt (3x)
for example if x = 12
y = sqrt(36) = 6
y = -sqrt(36) = -6
so there are two values of y for every x
NOT a function