Homework Help: Algebra

Posted by Sara on Friday, March 28, 2008 at 5:49pm.

Does this relation define a function?
y^2=3x
My answer:
3x=y^2|0|3|12|27
y |0|1| 2| 3
y^2=3x is a function because the coordinates I chose are not duplicated.

Algebra - Damon, Friday, March 28, 2008 at 6:07pm
y^2 = 3 x
y = + sqrt(3x)
BUT
y = - sqrt (3x)

for example if x = 12
y = sqrt(36) = 6
BUT
y = -sqrt(36) = -6
works
so there are two values of y for every x
NOT a function

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