Tuesday

July 29, 2014

July 29, 2014

Posted by **Bradley** on Friday, March 28, 2008 at 11:13am.

My problem is:

Compare the graph of the given quadratic function f and the graph of y=x2.

f(x)=(x-2)2+3

- Algebra HELP! -
**drwls**, Friday, March 28, 2008 at 11:26amI expect that you mean y = x^2 and

f(x) = (x-2)^2 + 3. We suggest you to use a ^ before all exponents to help us understand what you are writing.

Both curves are parabolas that open upward. The first one, "y" has its minimum value when x = 0, and the y value there is y = 0.

The second curve, f(x), has its minimum value at x = 2, and the y value there is f(x) = 3. One curve looks like the other, except that they are displaced to different regions of the graph.

- Algebra HELP! -
**Bradley**, Friday, March 28, 2008 at 1:18pmIf they are suppose to be exponents, that would make more sense. But my problem was written exactly as I typed it. So the answers they are looking for are the values of x, y, and f(x)? Thank-you for your help.

- Algebra HELP! -
**brenda**, Sunday, March 27, 2011 at 2:04am3x + 24y = 24 and 27x – 15y = -15

how do i solve using substitution method

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