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December 20, 2014

December 20, 2014

Posted by **Anonymous** on Thursday, March 27, 2008 at 11:12pm.

a) r = (-8,-1,8) + s(-5,1,4) + t(3,2,-4)

Scalar Equation: -12x - 8y - 13z = 0

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b) r = (-2,-2,5) + s(3,1,-1) + t(4,1,-4)

Scalar Equation: -3x + 8y - z + 15 = 0

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*****How do you determine if the planes are the same?

- Math: Scalar Equations of a Plane -
**Reiny**, Friday, March 28, 2008 at 9:15am(-5,1,4) and (3,2,-4) are two direction vectors on the first plane.

So we need a normal to these planes, the cross-product will give us that.

Which will be (12,8,13)

so the scalar equation will be

12x + 8y + 13z = D

(-8,-1,8) was given as a point on the plane, so

12(-8) + 8(-1) + 8(13) = D

D = 0

so the scalar equation is

12x + 8y + 13z = 0

Do the second one the same way.

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