Posted by Anonymous on Thursday, March 27, 2008 at 9:41pm.
Find the intersection of the first two lines:
subtract the first from the second
11y - 4z = 0
11y = 4z
y/z = 4/11
let y=4 and z=11 (it satisfies the above ratio)
back in the first
x - 8 - 11 = 0
x = 19
since clearly (0,0,0) lies on all three planes, the line joining (0,0,0) and (19,4,11) is the intersection line of the first two planes.
But all 3 planes are supposed to intersect in the same line, so obviously (19,4,11) must also lie on the third plane.
so sub it in....
k(19) - 8 - 11 = 0
k = 19/19 =1
so k=1
let l be th line x+1/2=y+3/3=-z and let P be the plane 3x-2y+4z=-1. find the piont of intersection po of l and p
let l be th line x+1/2=y+3/3=-z and let P be the plane 3x-2y+4z=-1. find the piont of intersection po of l and p
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