Algebra
posted by Kaylee .
A big sale is happening today at the Newton Shoe Store. You buy two pair od running shoes. The first pair is $64, which is 20% off the original price. The second pair os $72, which is 40% off the original price. what is the persent of discount on the Combined purchase os the two pairs of shoes? (assuming no sales tax is involved)
I know that you have to find the original prices of the shoes, then, add that together, then add the percents together, and find the total percent, correct?
I don't know how to get to the original price, or how to find the end percent. Can anyone help?
Thanks!

To find the original price:
Since the price for the first pair is 20% off the original price, you're actually paying 80% of the original price.
0.8x = 64
x = 64/0.8
x = 80
Using the same method, find the original price of the second pair.
We'll be glad to check your answer. 
would the second pair be $120?
then you add those together, and that equals $200.
Here's were I'm stuck.
Would you make the $200 a percent then subtract it by the sum of the 80% and 60%? your answer would be 50%. 
Yes. The original price of the second pair was $120  so the two pairs of shoes together would have cost $200.
But you paid only paid $136 for the twopairs.
To find the percent of discount for both pairs:
$200  136 = $64
64/200 = .32 = 32% 
Oh THANK YOU!!! i've benn so confused!