A locker combination has two nonzero digits, and digits can be used twice. The first number is 8. What is the probability that the second number is 8?
I am confused by your description. Does "two nonzero digits" mean that there are two digits beside zero? If so, how do you get an 8?
The answer would be 1 divided by the total number of possibilities.
I hope this helps. Thanks for asking.
A locker combination has two nonzero digits, and digits can be used twice. The first number is 8. What is the probability that the second number is 8?
To find the probability that the second number in the locker combination is 8, we need to determine the total number of possible combinations and the number of combinations where the second number is 8.
In this case, since the digits can be used twice, there are 10 possible options for each digit (0-9). But since the first number is already given as 8, there are only 9 possible options for the second number (since it cannot be 8 again).
So, the total number of possible combinations is 10 * 9 = 90.
Now, let's find the number of combinations where the second number is 8. Since the first number is already fixed at 8, there is only one option for the second number, which is 8.
Therefore, the number of combinations where the second number is 8 is 1.
Now we can calculate the probability by dividing the number of desired outcomes (the number of combinations where the second number is 8) by the total number of possible outcomes.
Probability = Number of desired outcomes / Total number of possible outcomes
Probability = 1 / 90 = 0.0111 (rounded to four decimal places) or approximately 1.11%.