Posted by **Brooke** on Thursday, March 27, 2008 at 5:05pm.

A locker combination has three nonzero digits, and digits cannot be repeated. If the first two digits are even, what is the probability that the third digit is even?

- math: probability -
**bobpursley**, Thursday, March 27, 2008 at 5:27pm
Assuming the digits are from 1 to 9, then the even is 2,4,6,8 and the odd are 1,3,5,7,9.

Prodd(ways/choices)=5/(2+5)

- math: probability -
**Ty'johnna**, Saturday, June 28, 2014 at 10:57pm
ex. 3 and 4 chance of something, it would be .75 because 4 (100) x 3 of 100 is 75 so its .75!

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