A certain kind of glass with index of refraction of 1.65 for blue light of wavelength 430nm and index of refraction 1.615 for red light with wavelength 680nm. If a beam of light containing these two colors has incident angle of 30 degrees what is the angle inside the glass?

I NEED HELP HERE IM TOTALLY LOST please help

Look up Snells law. Remember the two colors will have different angles in the glass, as the refractive index will bend them differently.

To find the angle inside the glass, we can use Snell's Law, which states:

n1 * sin(theta1) = n2 * sin(theta2)

where n1 and n2 are the indices of refraction of the two media (in this case, air and glass), and theta1 and theta2 are the incident and refracted angles, respectively.

Given:
- n1 (for air) is approximately 1 (since the index of refraction of air is very close to 1)
- n2 (for glass) is 1.65 for blue light (430nm) and 1.615 for red light (680nm)

First, let's find the angle of refraction for the blue light:

n1 * sin(theta1) = n2 * sin(theta2)

1 * sin(30 degrees) = 1.65 * sin(theta2)

sin(theta2) = (sin(30 degrees)) / 1.65
theta2 = arcsin((sin(30 degrees)) / 1.65)

Using a calculator, we find theta2 is approximately 17.45 degrees.

Now, let's find the angle of refraction for the red light:

n1 * sin(theta1) = n2 * sin(theta2)

1 * sin(30 degrees) = 1.615 * sin(theta2)

sin(theta2) = (sin(30 degrees)) / 1.615
theta2 = arcsin((sin(30 degrees)) / 1.615)

Using a calculator, we find theta2 is approximately 18.29 degrees.

Therefore, the beam of light containing both blue and red light will have an angle of approximately 17.45 degrees for the blue light and 18.29 degrees for the red light inside the glass.