Posted by **lyne** on Wednesday, March 26, 2008 at 10:04am.

k2=[H][SO4]/[HSO4]

.012=(.01+x)(x)/(.01-x)

Solve for x, and calculate pH where H is .01+x

When I am solving for x does it become

.012= .01x + x^2/ .01 -x.. what is the next step of solving for x?

- chemistry 1 -
**bobpursley**, Wednesday, March 26, 2008 at 10:56am
Next step, multiply both sides by (.01-x)

.012(.01-x)=.01x+x^2

gather terms, put in standard binomial form, use the quadratic equation, and solve for x.

Your question actually bothers me. You are asking an algebra 1 question in order to solve a very complicated chemistry question. Are you in over your head in chem math? You may want to discuss this with an academic counselor.

## Answer this Question

## Related Questions

- math - Next step, multiply both sides by (.01-x) .012(.01-x)=.01x+x^2 is the ...
- chemistry - Calculate the pH of the following aqueous solution: 1.00 mol/L ...
- chem - Next step, multiply both sides by (.01-x) .012(.01-x)=.01x+x^2 gather ...
- Calculus - Suppose that you can calculate the derivative of a function using the...
- chemistry - Calculate the pH of the following aqueous solutions: 1.00 mol/L ...
- math 012 - Hi, I am trying to do homework for my math 012 class- solving linear ...
- chem - What is the pH ( 3 significant digits) of a 0.01 M solution of sulfuric ...
- chem - DrBob has given you the equation to use: k2 = [H^+][SO4^-]/[HSO4^-] and ...
- chemistry - Posted by lyne on Tuesday, March 25, 2008 at 11:44pm. What is the pH...
- chemistry 12 - Identify the two conjugate acid-base pairs in each of the ...