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April 16, 2014

Homework Help: chemistry 1

Posted by lyne on Wednesday, March 26, 2008 at 10:04am.

k2=[H][SO4]/[HSO4]

.012=(.01+x)(x)/(.01-x)

Solve for x, and calculate pH where H is .01+x

When I am solving for x does it become

.012= .01x + x^2/ .01 -x.. what is the next step of solving for x?

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