Saturday

October 25, 2014

October 25, 2014

Posted by **lyne** on Wednesday, March 26, 2008 at 10:04am.

.012=(.01+x)(x)/(.01-x)

Solve for x, and calculate pH where H is .01+x

When I am solving for x does it become

.012= .01x + x^2/ .01 -x.. what is the next step of solving for x?

- chemistry 1 -
**bobpursley**, Wednesday, March 26, 2008 at 10:56amNext step, multiply both sides by (.01-x)

.012(.01-x)=.01x+x^2

gather terms, put in standard binomial form, use the quadratic equation, and solve for x.

Your question actually bothers me. You are asking an algebra 1 question in order to solve a very complicated chemistry question. Are you in over your head in chem math? You may want to discuss this with an academic counselor.

**Answer this Question**

**Related Questions**

chemistry - Calculate the pH of the following aqueous solution: 1.00 mol/L ...

Calculus - Suppose that you can calculate the derivative of a function using the...

chemistry - Calculate the pH of the following aqueous solutions: 1.00 mol/L ...

math 012 - Hi, I am trying to do homework for my math 012 class- solving linear ...

chem - What is the pH ( 3 significant digits) of a 0.01 M solution of sulfuric ...

chem - DrBob has given you the equation to use: k2 = [H^+][SO4^-]/[HSO4^-] and ...

chemistry - Posted by lyne on Tuesday, March 25, 2008 at 11:44pm. What is the pH...

chem - Next step, multiply both sides by (.01-x) .012(.01-x)=.01x+x^2 gather ...

chemistry 12 - Identify the two conjugate acid-base pairs in each of the ...

CHEM-PLEASE HELP - 1- Calculate the equilibrium concentration for H+, HSO4- and ...