Friday
July 25, 2014

Homework Help: chemistry 1

Posted by lyne on Wednesday, March 26, 2008 at 10:04am.

k2=[H][SO4]/[HSO4]

.012=(.01+x)(x)/(.01-x)

Solve for x, and calculate pH where H is .01+x

When I am solving for x does it become

.012= .01x + x^2/ .01 -x.. what is the next step of solving for x?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

chemistry - Calculate the pH of the following aqueous solution: 1.00 mol/L ...
Calculus - Suppose that you can calculate the derivative of a function using the...
chemistry - Calculate the pH of the following aqueous solutions: 1.00 mol/L ...
math 012 - Hi, I am trying to do homework for my math 012 class- solving linear ...
chem - What is the pH ( 3 significant digits) of a 0.01 M solution of sulfuric ...
chem - DrBob has given you the equation to use: k2 = [H^+][SO4^-]/[HSO4^-] and ...
chemistry - Posted by lyne on Tuesday, March 25, 2008 at 11:44pm. What is the pH...
chem - Next step, multiply both sides by (.01-x) .012(.01-x)=.01x+x^2 gather ...
chemistry 12 - Identify the two conjugate acid-base pairs in each of the ...
CHEM-PLEASE HELP - 1- Calculate the equilibrium concentration for H+, HSO4- and ...

Search
Members