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November 23, 2014

November 23, 2014

Posted by **Jessica** on Wednesday, March 26, 2008 at 1:20am.

a. r=2

b. r=3sin pheta

c.r^2=sin2pheta

I dont understand how to solve for this, especially for r squared. Would someone plz explain how o convert to a cartesian equation. any help would be greatly appreciated!

- Calc -
**Reiny**, Wednesday, March 26, 2008 at 10:11amThe relationships you need should be in your text, or you can find them at the top of

http://mathworld.wolfram.com/PolarCoordinates.html

your first one r = 2 is then quite easy

r = √(x^2 + y^2)

2 = √(x^2 + y^2)

x^2 + y^2 = 4 which is a circle

your second:

r=3sin pheta

r=3sinß

but sinß = y/r

r=3sinß

r = 3(y/r)

r^2 = 3y

x^2 + y^2 = 3y

for the third I can't tell if you mean

r^2 = sin(2ß) or r^2 = sin^{2}ß

I will let you decide and then follow my previous examples.

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