fred begins walking at three mi/h. john leaves his house at the same time and walks towards freds house at a rate of 2 mi/h. how long will it be befor thhey meet the distance between the two houses is 4 miles?
What is the time it takes for a person to walk 4 miles at 5 miles an hour?
MAke a 4 inch line and for every hr. they are supposed to walk. for john draw a dash 2 inches away from 1 end of the line. mimic this but for 3 inches for fred and find at what time they will meet.
To find out how long it will take for Fred and John to meet, we need to calculate the time it takes for them to cover the distance between their houses.
Let's assume that the time taken for them to meet is 't' hours.
For Fred, the distance covered will be:
Distance = Speed * Time
Distance = 3 mi/h * t hours
Distance = 3t miles
For John, the distance covered will be:
Distance = Speed * Time
Distance = 2 mi/h * t hours
Distance = 2t miles
Since they are walking towards each other, the total distance covered by both of them will be equal to the distance between their houses, which is 4 miles.
Total distance covered = Distance covered by Fred + Distance covered by John
4 miles = 3t miles + 2t miles
Now, let's solve the equation for 't':
4 miles = 3t miles + 2t miles
4 miles = 5t miles
Divide both sides of the equation by 5:
(4 miles) / 5 = (5t miles) / 5
0.8 miles = t miles
Therefore, it will take them 0.8 hours, or 48 minutes, to meet each other.
To summarize:
Fred and John will meet in 0.8 hours, or 48 minutes.