5 (6-2x) = -3 (-2x + 6)
whats the value of x in each
(has to be the same)
5(6-2x)=.3(-2x+6)
30-10x=-0.6x+1.8
10x+0.6=30-1.8
9.4x=28.2
9.4/9.4 and 28.2/9.4
x=3
Are you trying to solve the one equation for x? If so, what is your problem? What don't you understand about the problem?
my answer was wrong i thought it said .3 not -3 let me rework the problem for you
5(6-2x)=-3(-2x+6)
30-10x=-6x-18
30+18=-6x-18
30+18=-6x+10
48=4x
48/4 and 4x/4
x=12
SOMEONE GO BEHIND MY WORK AND MAKE SURE THAT I AM CORRECT!!
To find the value of x that satisfies the given equation, let's start by simplifying both sides of the equation:
5(6-2x) = -3(-2x + 6)
First, distribute the 5 and -3:
30 - 10x = 6x - 18
Now, let's group like terms by adding 10x to both sides of the equation:
30 - 10x + 10x = 6x - 18 + 10x
30 = 16x - 18
Next, we add 18 to both sides of the equation:
30 + 18 = 16x - 18 + 18
48 = 16x
To solve for x, divide both sides of the equation by 16:
48/16 = 16x/16
3 = x
Therefore, the value of x that satisfies the given equation is x = 3.