Posted by **scooby doo** on Tuesday, March 25, 2008 at 8:17pm.

lois rode her bike to visit a friend. She traveled at 10 miles an hour. While she was there it began to rain. Her friend drove her home at 25 miles per hour. Lois took 1.5 hours longer to go to a friends then to return home. How many hours did it take Lois to arrive at her friend's house?

- algebra 1 -
**DrBob222**, Tuesday, March 25, 2008 at 8:29pm
distance = rate x time.

return trip = 25 mph x time

going = 10 mph x (time + 1.5)

distance is the same; therefore, set them equal to each other.

25t = (10(t+1.5)

solve for time

time + 1.5 = time it took Lois to go to her friends house. Post your work if you get stuck.

- algebra 1 -
**drwls**, Tuesday, March 25, 2008 at 8:29pm
Call the two times t1 and t2. Call the distance between points D.

D = 10 t1

D = 25 t2

t1 = t2 + 1.5

t1 = 2.5 t2 would be a good substitution in the last equation. Then you will have one equation on one unknown (t2). Once you have that, you can compute t1.

- algebra 1 -
**Nikky**, Monday, February 24, 2014 at 8:41pm
T=1, 1hour

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