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July 30, 2014

July 30, 2014

Posted by **scooby doo** on Tuesday, March 25, 2008 at 8:17pm.

- algebra 1 -
**DrBob222**, Tuesday, March 25, 2008 at 8:29pmdistance = rate x time.

return trip = 25 mph x time

going = 10 mph x (time + 1.5)

distance is the same; therefore, set them equal to each other.

25t = (10(t+1.5)

solve for time

time + 1.5 = time it took Lois to go to her friends house. Post your work if you get stuck.

- algebra 1 -
**drwls**, Tuesday, March 25, 2008 at 8:29pmCall the two times t1 and t2. Call the distance between points D.

D = 10 t1

D = 25 t2

t1 = t2 + 1.5

t1 = 2.5 t2 would be a good substitution in the last equation. Then you will have one equation on one unknown (t2). Once you have that, you can compute t1.

- algebra 1 -
**Nikky**, Monday, February 24, 2014 at 8:41pmT=1, 1hour

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