Posted by scooby doo on Tuesday, March 25, 2008 at 8:17pm.
distance = rate x time.
return trip = 25 mph x time
going = 10 mph x (time + 1.5)
distance is the same; therefore, set them equal to each other.
25t = (10(t+1.5)
solve for time
time + 1.5 = time it took Lois to go to her friends house. Post your work if you get stuck.
Call the two times t1 and t2. Call the distance between points D.
D = 10 t1
D = 25 t2
t1 = t2 + 1.5
t1 = 2.5 t2 would be a good substitution in the last equation. Then you will have one equation on one unknown (t2). Once you have that, you can compute t1.
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