Sunday

March 29, 2015

March 29, 2015

Posted by **Beth Macbeth** on Monday, March 24, 2008 at 11:31am.

I don't know what equation to use. Any help would be greatly appreciated.

- *physics* -
**bobpursley**, Monday, March 24, 2008 at 11:58amYou know the KE of the electrons. They can pass this quantized energy to the hydrogen atom. Set this equal to 13.6v

http://musr.physics.ubc.ca/~jess/hr/skept/QM1D/node4.html

or

12.87>13.6 (1/n^2 - 1/m^2) What n, m will work? The longest wavelength will occur at the least energy, or n is very large, and m is infinity. So the question bothers me, if it read calculate the shortest wavelength, then energy would be as close to 12.87 as possible, the highest frequency (low wavelength). So if it is that, then n=1, m=very large will work. Then

12.87=plancks constant(c/lambda) and you can calculate lambda. But again, this is the shortest wavelength.

Check my thinking.

**Answer this Question**

**Related Questions**

physics - 5)a. Electrons accelerated by a potential difference of 12.23 V pass ...

Atomic physics - 5)a. Electrons accelerated by a potential difference of 12.23 V...

Physics - A tungsten target is struck by electrons that have been accelerated ...

physics - A tungsten target is struck by electrons that have been accelerated ...

Physics please help! - A tungsten target is struck by electrons that have been ...

Physics-PLEASE HELP ASAP - A tungsten target is struck by electrons that have ...

Physics Please Help ASAP - A tungsten target is struck by electrons that have ...

chemistry - Electron exhibiting a particle wavelength of 6.81 x 10-9 are emitted...

Chemistry - Electron exhibiting a particle wavelength of 5.2 x 10-9 are emitted ...

Chemistry - Electron exhibiting a particle wavelength of 4.02 x 10-9 are emitted...