Friday

April 18, 2014

April 18, 2014

Posted by **Bobby** on Sunday, March 23, 2008 at 6:11pm.

2. If a sphere of radius 2 meters is placed in a uniform electric field of 3 N/C, what is the net flux through the sphere?

3. Show how Gauss's Law can be used to derive Coulomb's law for a single charge. Explain any simplifications and draw your Gaussian surface.

- Physics-Gauss' Law -
**Damon**, Sunday, March 23, 2008 at 6:24pm100 in the x direction or 100 i

the cross section hit perpendicular to the field is pi r^2

draw sphere centered at origin around charge Q at origin

By symmetry E is constant over surface of sphere at any radius r (surface area 4 pi r^2)

net flux through surface of sphere = E*(4 pi r^2) = Q /eo

so

E = Q/(4 pi r^2 eo)

done

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