Posted by **POD** on Sunday, March 23, 2008 at 11:53am.

in a triangle BCA there are three medians b,c,a. Prove that

3(A^2+B^2+C^2)=4(a^2+b^2+c^2)

(sides) = (medians)

## Answer this Question

## Related Questions

- Math - A triangle has vertices X(0,0), Y(4,4), and Z (8,-4). a) Write an ...
- Geometry - How do you find the lengths of the sides of an isosceles triangle ...
- geometry - If two medians of a triangle are equal, prove that the triangle ...
- Math - 12. In a triangle ABC, AC = 36, BC = 48, and the medians BD and AE to ...
- geometry - Write a two column proof. Given CE = CA, EB and AD are medians, Prove...
- geometry question proof needed - Medians AX and BY of Triangle ABC are ...
- Geometry - Given a triangle ABC with A(6b,6c) B(0,0) and C (6a,0), prove that ...
- Math - In a triangle ABC, AC = 36, BC = 48, and the medians BD and AE to sides ...
- Geometry: Ms. Sue or Steve or someone help please? - Given a triangle ABC with A...
- geometry - show that the sum of the squares of the lengths of the medians of ...

More Related Questions