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August 27, 2014

August 27, 2014

Posted by **Zoe** on Saturday, March 22, 2008 at 2:19pm.

A hunter is standing on flat ground between two vertical cliffs that are directly opposite one another. He is closer to one cliff than the other. He fires a gun and , after a while, hears three echoes. The second echo arrives 1.6s after the first, and the third echo arrives 1.1s after the second. Assuming that the speed of sound is 343m/s and that there are no reflections of sound from the ground, find the distance between the cliffs.

- ap physics -
**bobpursley**, Saturday, March 22, 2008 at 3:44pmThe first echo is from the nearer clift. The second is from the farther clift. The third is from the nearer clift (second echo on that path from the farther clift).

Let N be the distance from nearer clift.

Let F be teh distance from the farther clift.

2N=v t

2F=v(1.6+t)

2F+2N=v(1.1+1.6+t)

Three equations, you can solve for all three, and you want to find F+N.

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