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May 4, 2015

May 4, 2015

Posted by **Mikal** on Saturday, March 22, 2008 at 4:26am.

r^64-1 = 2.5x10^7 (r-1)

any ideas?

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**Reiny**, Saturday, March 22, 2008 at 9:21amr-1 is a factor of r^64 - 1 so use synthetic division (notice the pattern) to divide both sides by r-1 to get

r^63 + r^62 + ... + r + 1 = 2.5(10)^7

the left side is a geometric series with

a = 1

common ratio = r

n = 64

so the sum of the left side = 1(r^64 - 1)/63

then (r^63 - 1)/63 = 2.5(10^7

r^63 = 63(2.5)(10)^7 + 1

taking the 63rd root I got

r = 1.3922

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**Reiny**, Saturday, March 22, 2008 at 9:46amOOOPS, just looked at my solution again and

I'm WRONG!!! (must have had an early morning synapse collapse)

The sum of my series should have said

1(r^64 - 1)/(r-1)

then r^64 - 1 = 2.5(10)^7(r-1)

which brings me back to what we started with.

Arggh!!!

Sorry, looks like we would have to use some method such as Newtons's Method or some kind of "equation solver" program.

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