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October 20, 2014

October 20, 2014

Posted by **Jim** on Friday, March 21, 2008 at 8:41pm.

t^2+14t+49=0

The value of the discriminant is 0 and the equation has no real solution.

- Algebra Problem -
**Reiny**, Friday, March 21, 2008 at 9:10pmNo

If the discriminant is zero, then the quadratic factors to a perfect square, and there will be one real solution (actually two real but equal solutions)

t^2+14t+49=0

(t+7)^2 = 0

t+7 = 0

t = -7

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