Can someone tell me if these problems have the right answers? I am tooooooo old to know this any more. I understand the first one, but 2&3 are vaguely familiar.

25x^2+25x+6=0
the answer is x=-1/2 +/- 1/10

#2 solve for V=1/3Bh for B
answer is B=V/ 1/3h

#3 Find equation of line (-4,-3) and (5,6)
answer is 1x+y=-4

the first one is wrong

25x^2+25x+6=0 factors to
(5x+2)(5x+3) = 0
so x = -2/5 or x = -3/5

in the second one
V=1/3Bh multiply both sides by 3
3V = Bh now divide both sides by h
3V/h = B

no for the third one, sorry 3 strikes!

most students appear to be taught the
y = mx + b method

so slope = m = 9/9 = 1

so y = x + b
sub in one of the points, say (5,6)

6 = 5 + b
b = 1

so the equation is y = x + 1 or
x - y = -1

(test the two given points, they both work. They don't work in your equation)

#3 He has the m=9/9 slope

the 6 and 5 are written m=6-(-3)/5-(-4), so he has a - sign where there should be a plus sign? He must be using the wrong formula, because at the beginning he has m=y2-y1/x2-x1. The numbers 2&1 are below the y and x. Hehas used the formula y=mx+b before.

the slope is indeed 9/9 which is 1

so m=1

the calculations for slope are correct, I don't like the way you typed them.
You have to use brackets to control the proper order of operation, so your

m=6-(-3)/5-(-4) should be written as
m=(6-(-3)) / (5-(-4))
m = (6+3) / (5+4) because 6 - (-3) = 6 + (3)
m = 9/9
m =1

m=y2-y1/x2-x1 is simply the formula used to find slope if you are given two points.
it means take (the y of the second point - the y of the first point), then divide it by (the x of the second point - the x of the first point)

Sure! I'd be happy to help you check the answers to these problems.

Let's go through each problem step by step:

Problem #1:
The equation is 25x^2 + 25x + 6 = 0.

To find the solutions for x, you need to use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a).

In this equation, a = 25, b = 25, and c = 6. Now we can substitute these values into the quadratic formula to find the answers for x:

x = (-25 ± √(25^2 - 4*25*6)) / (2*25)
x = (-25 ± √(625 - 600)) / 50
x = (-25 ± √25) / 50
x = (-25 ± 5) / 50

Simplifying further:
x = (-25 + 5) / 50 --> x = -20/50 = -1/2
x = (-25 - 5) / 50 --> x = -30/50 = -3/5

So, the correct answers are x = -1/2 and x = -3/5.

Problem #2:
Solving for B in the equation V = (1/3)Bh.

To isolate B, we can start by multiplying both sides of the equation by 3 to get rid of the fraction:
3V = Bh

Next, we want to get B alone, so divide both sides of the equation by h:
(3V) / h = B

So, the correct answer is B = 3V / h.

Problem #3:
Finding the equation of a line given two points: (-4, -3) and (5, 6).

The equation of a line can be determined using the slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept.

To find the slope (m) of the line passing through these two points, we use the slope formula:
m = (y2 - y1) / (x2 - x1)

Substituting the values of the given points:
m = (6 - (-3)) / (5 - (-4))
m = (6 + 3) / (5 + 4)
m = 9 / 9
m = 1

Now that we have the slope, we can substitute one of the given points and the slope into the slope-intercept form to find the y-intercept (b):
y = mx + b
-3 = 1 * (-4) + b
-3 = -4 + b
b = -3 + 4
b = 1

So, the equation of the line is y = x + 1.

I hope this helps! Let me know if you have any further questions.