Posted by Sara on Friday, March 21, 2008 at 6:40pm.
find center and radius of circle
(x6)^2+(y+9)^2=121
(x6)^2 (x6)^2
(y+9)^2=121121(x6)^2
(y+9)^2=+/ ã121(x6)^2
9 9
y=9+/ã121(x6)^2
does anyone know is this the answer or do I go further???????????????????????

algebra  Reiny, Friday, March 21, 2008 at 7:01pm
Your equation is already in the standard form of
(xh)^2 + (yk)^2 = r^2
where (h,k) is the centre and the radius is r
so for (x6)^2+(y+9)^2=121
the centre is (6,9) and the radius is 11
I have no clue what you were trying to do in your solution
.
Also this is the third student who has statements like your
9 9
in a sequential solution.
What is that supposed to mean?
Are you all from the same class? 
algebra  Anonymous, Friday, March 21, 2008 at 7:11pm
I know Lori. We are suppose to show the number we left out or took away.

algebra  Reiny, Friday, March 21, 2008 at 7:28pm
Where are they showing you that way?
Tell me the city or state or province, don't name the school