Algebra
posted by Bethany on .
HELP!
an object moves in a straight line given by s=2x^23t where s is in meters and t is the time in seconds the object is in motion. how long to nearest tenth will it take to move 17 meters?
my attempt
s=2t^23t
17=2t^23t
17=17
0=2t^23x17
t=b +or sqrtb^24ac/2a
t=(3)+orsqrt3^24(2)(17)/2(2)
Did I do all of the correct steps? I think I did but this is really confusing

I have worked it more.....
t=3+orsqrt9+136/4
t=3+orsqrt145/4 (is this my answer?) 
yes, you are right, but when typing on here you should use brackets to establish the correct order of operation
t = (3 ± √145)/4
I got the ± by holding down the Alt key and at the same time punching in 241 on the number key pad, then releasing the Alt key
I got the √ by holding down the Alt key and at the same time punching in 251 on the number key pad, then releasing the Alt key
I am using a PC with Firefox on XP
It did not work on my Apple IBook laptop