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April 19, 2014

April 19, 2014

Posted by **Bethany** on Friday, March 21, 2008 at 1:11pm.

an object moves in a straight line given by s=2x^2-3t where s is in meters and t is the time in seconds the object is in motion. how long to nearest tenth will it take to move 17 meters?

my attempt

s=2t^2-3t

17=2t^2-3t

-17=-17

0=2t^2-3x-17

t=-b +or- sqrtb^2-4ac/2a

t=-(-3)+or-sqrt-3^2-4(2)(-17)/2(2)

Did I do all of the correct steps? I think I did but this is really confusing

- Algebra -
**Bethany**, Friday, March 21, 2008 at 1:32pmI have worked it more.....

t=3+or-sqrt9+136/4

t=3+or-sqrt145/4 (is this my answer?)

- Algebra -
**Reiny**, Friday, March 21, 2008 at 5:48pmyes, you are right, but when typing on here you should use brackets to establish the correct order of operation

t = (3 ± √145)/4

I got the ± by holding down the Alt key and at the same time punching in 241 on the number key pad, then releasing the Alt key

I got the √ by holding down the Alt key and at the same time punching in 251 on the number key pad, then releasing the Alt key

I am using a PC with Firefox on XP

It did not work on my Apple IBook laptop

- Algebra -

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