Posted by Maria Lewis on .
Two charges are arranged on the x axis so that there is a positive charge of 3.6 micro C at the orgin and a negative charge of .2.5 micro C located 2.5 centimeters to its right. to the nearest cetimeter, where on the x axis should a positive charge be placed so that the net force on it is zero?

Physics 
bobpursley,
Let the charge be to the right of the negative charge, and see if one can get a solution
F1 + F2=0
k3.6*q/x^2  k2.5q/(x2.5)^2=0
solve for x.