Posted by Maria Lewis on .
Two charges are arranged on the x axis so that there is a positive charge of 3.6 micro C at the orgin and a negative charge of .2.5 micro C located 2.5 centimeters to its right. to the nearest cetimeter, where on the x axis should a positive charge be placed so that the net force on it is zero?
Let the charge be to the right of the negative charge, and see if one can get a solution
F1 + F2=0
k3.6*q/x^2 - k2.5q/(x-2.5)^2=0
solve for x.