What would be the velocity of a falling object after 8 seconds of free fall?
g t = 9.8 m/s^2 * 8 s = 78.4 m/s, neglecting air resistance
Rocks fall faster than pillows, for example. After 8 s the difference will be noticeable.
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To find the velocity of a falling object after 8 seconds of free fall, we need to use the formula for free fall:
v = gt
Where:
v is the velocity of the object
g is the acceleration due to gravity (which is approximately 9.8 m/s^2 on Earth)
t is the time in seconds
Plugging in the values given:
v = 9.8 m/s^2 * 8 s
v = 78.4 m/s
Therefore, the velocity of the falling object after 8 seconds of free fall would be 78.4 m/s.
To calculate the velocity of a falling object after a given time of free fall, we need to use the kinematic equation for free fall:
v = u + gt
Where:
v = final velocity of the object
u = initial velocity of the object (in this case, 0 m/s because the object is falling freely)
g = acceleration due to gravity (approximately 9.8 m/s² on Earth)
t = time in seconds
Since the initial velocity is 0 m/s, the equation simplifies to:
v = gt
Plugging in the values, we have:
v = (9.8 m/s²) * (8 s)
v = 78.4 m/s
Therefore, the velocity of the falling object after 8 seconds of free fall would be 78.4 m/s.