Posted by Agnes on Thursday, March 20, 2008 at 12:43pm.
Interval, or integral?
I suggest you split it up into
4 sec^2 (theta)
+ 4 sin(theta)/cos^2(theta)
You can find the integral of the first one in a table of integrals. The second one is easy if you let u = cos theta and du = -sin theta dtheta
The integral of sec^2 is tan
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