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Interval 4sec(theta)(sec(theta)+tan(theta))d(theta)

can someone help me start his problem?

  • Calculus - ,

    Interval, or integral?

    I suggest you split it up into
    4 sec^2 (theta)
    + 4 sin(theta)/cos^2(theta)

  • Calculus - ,

    You can find the integral of the first one in a table of integrals. The second one is easy if you let u = cos theta and du = -sin theta dtheta

  • Calculus - ,

    The integral of sec^2 is tan

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