Posted by Tri on Thursday, March 20, 2008 at 3:13am.
A baseball is hit at 35.0m/s at an angle of 25.0 degrees to the horizontal.
How high will the ball go>
When will it reach that height?
How far across the baseball field will the ball travel?
Thanks.

Physics  tchrwill, Thursday, March 20, 2008 at 9:45am
How high will the ball go>
When will it reach that height?
How far across the baseball field will the ball travel?
The height reached is derivable from h = V^2(sin^2(µ)/2g where V = the launch velocity, µ = the launch angle and g = the acceleration due to gravity.
Using the verical component of the launch velocity, the time to reach the maximum height derives from Vf = Vo  gt where Vf = the final vertical velocity = 0, Vo = the initial vertical velocity = 25sin25º and g is as defined earlier.
The horizontal distance traveled derives from d = V^2sin(2µ)/2g.