Posted by **Tri** on Thursday, March 20, 2008 at 3:13am.

A baseball is hit at 35.0m/s at an angle of 25.0 degrees to the horizontal.

How high will the ball go>

When will it reach that height?

How far across the baseball field will the ball travel?

Thanks.

- Physics -
**tchrwill**, Thursday, March 20, 2008 at 9:45am
How high will the ball go>

When will it reach that height?

How far across the baseball field will the ball travel?

The height reached is derivable from h = V^2(sin^2(µ)/2g where V = the launch velocity, µ = the launch angle and g = the acceleration due to gravity.

Using the verical component of the launch velocity, the time to reach the maximum height derives from Vf = Vo - gt where Vf = the final vertical velocity = 0, Vo = the initial vertical velocity = 25sin25º and g is as defined earlier.

The horizontal distance traveled derives from d = V^2sin(2µ)/2g.

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