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November 28, 2014

November 28, 2014

Posted by **Karen** on Wednesday, March 19, 2008 at 7:08pm.

find the value of the final equilibrium concentrations of all reactants and products of M?

so far this is what i have:

When converting I2 to mols I got 0.0226 mols and divided by 5.00L gives me 0.00452 M.

For Br 2 i got 0.0307 mol and divided by 5.00 L gives me 0.00614 M.

(Q=0 b/c no products exist initially)

i would prefer to use as simple math as possible, so i didn't use multiple variables.

let 2x=IBr

x=I2

x=Br2

so the expression from that is:

2x^2/(0.00452-x)(0.00614-x)=125

when expanded, for the polynomial, i calculated

4x^2/(2.76X10^-5 - 0.00452x-0.00641x - .00345)

4x^2 = 125x^2-.7675X-.565x-.00345

0 = 121x^2 - .7675x-.565x-.00345

so i solved for x using the quadratic formula and i recieved

-1.3325+- square root(-1.3325)^2-4(125)(.000345)/ 2(121)

-1.3325+-.3253/242

x=-.00685 and -.50365 that can't be right can it?

negative values wouldn't work for the domain correct?

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