Tuesday

October 21, 2014

October 21, 2014

Posted by **Steve** on Wednesday, March 19, 2008 at 4:32pm.

The answers are 1.07 x10^4 m/s, 1.17 x10^4 m/s and 1.12 x10^4 m/s. I got c but I don't understand what to do for a and b.

- Physics -
**tchrwill**, Wednesday, March 19, 2008 at 5:29pmEscape velocity is Ve = sqrt(2µ/r) where µ = the gravitational constant of the earth = 3.9863x10^14m^3/sec.^2 and r = the radius of the earth = 3963 miles = 6.377519x10^6 meters.

The earth's surface velocity at the equator is [3963(5280)2(3.1416)/3.281]/[86,400sec. = .0463m/s.

The vertical escape velocity is therefore 1.1180m/s.

Launching eastward, the escape velocity for the rockets 1.1180 - .0463 = 1.0707m/s.

Launchung westward, the escape velocity is 1.1180 + .0463 = 1.1643m/s.

**Answer this Question**

**Related Questions**

Physics - Take into account the Earth's rotational speed (1 rev/day) and use 5 ...

Physics - Take into account the Earth's rotational speed (1 rev/day) and ...

science - The true speed of a moving car on the Earth, if you want to be very ...

physics help - The earth orbits the sun once a year (3.16 10^7 s) in a nearly ...

Physics - If a projectile is launched from Earth with a speed equal to the ...

physics - If a projectile is launched vertically from the Earth with a speed ...

Physics - A projectile is fired vertically from Earth's surface with an initial ...

physics - The earth orbits the sun once a year (3.16 107 s) in a nearly circular...

Physics - A spaceship is launched from the Earth's surface with a speed v. The ...

Physics - A spaceship is launched from the Earth's surface with a speed v. The ...