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December 17, 2014

December 17, 2014

Posted by **Ted** on Wednesday, March 19, 2008 at 10:35am.

- calculus, again -
**Reiny**, Wednesday, March 19, 2008 at 11:38amtake the log of both sides

log(5^2x) = log (3^(x+1))

2xlog5 = (x+1)log3

2xlog5 = xlog3 + log3

2xlog5 - xlog3 = log3

x(2log5 - log3) = log 3

x = log3/(2log5 - log3)

x = .5181489...

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