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April 21, 2014

April 21, 2014

Posted by **J** on Tuesday, March 18, 2008 at 6:55pm.

Ok I got part (a) as being 75.82 V...but I am totally confused on part b I don't know what it is asking for or any equation that would work for it! Help please!

- Physics -
**Damon**, Tuesday, March 18, 2008 at 7:50pmI suppose maybe they mean what is the resistance you will see on the primary side.

Now the power on the secondary side is

P = V^2/R = (75.8)^2 / 125

P = 46 watts

Now I suppose we assume a perfect transformer so we put in that 46 watts on the primary side

46 = 25^2/R

R = 625/46 = 13.6 ohms

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