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September 20, 2014

September 20, 2014

Posted by **Casey** on Tuesday, March 18, 2008 at 1:26pm.

- algebra -
**Reiny**, Tuesday, March 18, 2008 at 3:49pmThe key thing is that when B catches A, they will have both traveled the same distance from the station, except A would have taken 12 minutes or 1/5 hour longer.

let the time taken by A be t hours, and the time taken by B be t-1/5 hours

so 60t = 70(t-1/5)

60t = 70t - 14

t = 1.4 or 1 hour 24 minutes after A left the station, which would make it

7:34

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