Posted by Claire on .
Given that the Earth's radius is 6.37x10^6 m and taking the earth's gravitational field at its surface to be 9.81N/kg, find the gravitational potential at the Earth's surface.

Physics 
bobpursley,
V=G*massearth/r
Where G*Massearth/r^2=9.81N/kg so
G*Massearth/r * r=9.81N/kg
So V= 9.81/r if r is in meters.
watch the units.