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January 28, 2015

January 28, 2015

Posted by **Jeff** on Tuesday, March 18, 2008 at 2:22am.

4x 5x

----- - ----

x^2-9 x^2+4x-+3

I am really confused on the -+3 part, I don't know if my teacher made a typo or what, because without the - in that part it would be easily factorable.

- Algebra -
**Jeff**, Tuesday, March 18, 2008 at 2:23amoops it didnt write the question like i wanted it to, here I'll fix it

4x/x^2-9 - 5x/x^2+4x-+3

- Algebra -
**drwls**, Tuesday, March 18, 2008 at 3:28amI also think the -+ is a typo error by your teacher. Assume it is +

Then you have

4x/[(x+3)(x-3)] - 5x/[(x+3)(x+1)]

= [1/(x+3)][4x(x+1)-5x(x-3)]/[(x+1)(x-3)]

= [1/(x+3)][-x^2+19x]/[(x+1)(x-3)]

= -x(x-19)/[(x+1)(x-3)(x+3)]

I don't guarantee I did that right. I created a common denominator, but it is still pretty messy.

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