Posted by Lucy on Monday, March 17, 2008 at 6:28pm.
the key is to recognize
both 81 and 243 as powers of 3
81 = 3^4 and 243 = 3^5
so (1/81)^t=243^t-2
(3^-4)^t = (3^5)^(t-2)
3^(-4t) = 3^(5t-10)
then -4t = 5t - 10
-9t=-10
t=10/9
Related Questions
Algebra II - Please check answers: Use the equation of the exponential function ...
Algebra II - Write the equation log243(81)=4/5 in exponential form. My answer is...
Algebra II - (3 radical 3)^4= 3^4 (radical 3)^4 = 81 radical 81 = 81 *3 radical ...
algebra - Solve each equation by factoring. 7x²-243=0 I know I'm ...
Math - Find X 27^4x-2=243^3x+6 Please explain how to do it. Thanks 27^(4x-2)=243...
algebra - what is the 10th term of the sequence 81,27,9 can someone plaese ...
math - A score of 243 is a "basic" reading level. Scores for a random ...
math - A score of 243 is a "basic" reading level. Scores for a random ...
Sequence - What is the fifth term of the sequence a sub n = 1/3^n? a)1/12 b)1/81...
Math 117 - 1.) A rectangular solid and a circular cylinder have the same volume ...
For Further Reading