Posted by **hokoslavia** on Sunday, March 16, 2008 at 6:38pm.

confrused with this one too let f(x)=x^2+6 and g (x) =4x-5 find (f ° g)(-7)

- algebra -
**Damon**, Sunday, March 16, 2008 at 6:56pm
just plod along

first do g(-7)

then do f(whatever you got for g)

- algebra -
**Damon**, Sunday, March 16, 2008 at 7:32pm
g(-7) = 4(-7) - 5 = -28 - 5 = -33

f(-33) = (-33)^2 + 6 = 1095 ???

- algebra -
**hokoslavia**, Sunday, March 16, 2008 at 7:46pm
according to my multiple choices its a fraction a -55/7 b 384/7 c 295/49 d 63/55

- algebra -
**Damon**, Sunday, March 16, 2008 at 7:51pm
Then there is a typo somewhere. There was no divide in the problem statement. Perhaps at x = -1/7 ??

- algebra -
**hokoslavia**, Sunday, March 16, 2008 at 7:56pm
f(x)=x^2+6 and g (x) =x +8/xfind (f ° g)(-7) yep there was sorry

- algebra -
**Damon**, Sunday, March 16, 2008 at 8:00pm
are you absolutely sure g(x) is not (x+8)/x ??

- algebra -
**Damon**, Sunday, March 16, 2008 at 8:03pm
if g(x) = (x+8)/x

then

g(-7) = -1/7

then

f(-1/7) = 1/49 + 6

= 1/49 + 294/49

= 295/49

- algebra -
**Damon**, Sunday, March 16, 2008 at 8:07pm
BUT

if it is as you wrote it

f(x)=x^2+6 and g (x) =x +8/xfind (f ° g)(-7) yep there was sorry

then

g(-7) = -7 + 8/-7

= -49/7 - 8/7=

= -57/7

the f(-57/7) = 57^2/49 +294/49

=3249/49 + 294/49

= 3543/49

which is not even on the list

- algebra -
**Damon**, Sunday, March 16, 2008 at 8:09pm
You are welcome

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