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algebra

posted by on .

confrused with this one too let f(x)=x^2+6 and g (x) =4x-5 find (f ° g)(-7)

  • algebra - ,

    just plod along

    first do g(-7)

    then do f(whatever you got for g)

  • algebra - ,

    i got -55/7 is that right?

  • algebra - ,

    g(-7) = 4(-7) - 5 = -28 - 5 = -33

    f(-33) = (-33)^2 + 6 = 1095 ???

  • algebra - ,

    according to my multiple choices its a fraction a -55/7 b 384/7 c 295/49 d 63/55

  • algebra - ,

    Then there is a typo somewhere. There was no divide in the problem statement. Perhaps at x = -1/7 ??

  • algebra - ,

    f(x)=x^2+6 and g (x) =x +8/xfind (f ° g)(-7) yep there was sorry

  • algebra - ,

    are you absolutely sure g(x) is not (x+8)/x ??

  • algebra - ,

    if g(x) = (x+8)/x
    then
    g(-7) = -1/7
    then
    f(-1/7) = 1/49 + 6
    = 1/49 + 294/49
    = 295/49

  • algebra - ,

    BUT
    if it is as you wrote it

    f(x)=x^2+6 and g (x) =x +8/xfind (f ° g)(-7) yep there was sorry

    then
    g(-7) = -7 + 8/-7
    = -49/7 - 8/7=
    = -57/7
    the f(-57/7) = 57^2/49 +294/49
    =3249/49 + 294/49
    = 3543/49
    which is not even on the list

  • algebra - ,

    ok then the other one is right im sorry and thank you

  • algebra - ,

    You are welcome

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