Posted by hokoslavia on .
confrused with this one too let f(x)=x^2+6 and g (x) =4x5 find (f ° g)(7)

algebra 
Damon,
just plod along
first do g(7)
then do f(whatever you got for g) 
algebra 
hokoslavia,
i got 55/7 is that right?

algebra 
Damon,
g(7) = 4(7)  5 = 28  5 = 33
f(33) = (33)^2 + 6 = 1095 ??? 
algebra 
hokoslavia,
according to my multiple choices its a fraction a 55/7 b 384/7 c 295/49 d 63/55

algebra 
Damon,
Then there is a typo somewhere. There was no divide in the problem statement. Perhaps at x = 1/7 ??

algebra 
hokoslavia,
f(x)=x^2+6 and g (x) =x +8/xfind (f ° g)(7) yep there was sorry

algebra 
Damon,
are you absolutely sure g(x) is not (x+8)/x ??

algebra 
Damon,
if g(x) = (x+8)/x
then
g(7) = 1/7
then
f(1/7) = 1/49 + 6
= 1/49 + 294/49
= 295/49 
algebra 
Damon,
BUT
if it is as you wrote it
f(x)=x^2+6 and g (x) =x +8/xfind (f ° g)(7) yep there was sorry
then
g(7) = 7 + 8/7
= 49/7  8/7=
= 57/7
the f(57/7) = 57^2/49 +294/49
=3249/49 + 294/49
= 3543/49
which is not even on the list 
algebra 
hokoslavia,
ok then the other one is right im sorry and thank you

algebra 
Damon,
You are welcome