Posted by hokoslavia on Sunday, March 16, 2008 at 6:38pm.
confrused with this one too let f(x)=x^2+6 and g (x) =4x5 find (f ° g)(7)

algebra  Damon, Sunday, March 16, 2008 at 6:56pm
just plod along
first do g(7)
then do f(whatever you got for g)

algebra  Damon, Sunday, March 16, 2008 at 7:32pm
g(7) = 4(7)  5 = 28  5 = 33
f(33) = (33)^2 + 6 = 1095 ???

algebra  hokoslavia, Sunday, March 16, 2008 at 7:46pm
according to my multiple choices its a fraction a 55/7 b 384/7 c 295/49 d 63/55

algebra  Damon, Sunday, March 16, 2008 at 7:51pm
Then there is a typo somewhere. There was no divide in the problem statement. Perhaps at x = 1/7 ??

algebra  hokoslavia, Sunday, March 16, 2008 at 7:56pm
f(x)=x^2+6 and g (x) =x +8/xfind (f ° g)(7) yep there was sorry

algebra  Damon, Sunday, March 16, 2008 at 8:00pm
are you absolutely sure g(x) is not (x+8)/x ??

algebra  Damon, Sunday, March 16, 2008 at 8:03pm
if g(x) = (x+8)/x
then
g(7) = 1/7
then
f(1/7) = 1/49 + 6
= 1/49 + 294/49
= 295/49

algebra  Damon, Sunday, March 16, 2008 at 8:07pm
BUT
if it is as you wrote it
f(x)=x^2+6 and g (x) =x +8/xfind (f ° g)(7) yep there was sorry
then
g(7) = 7 + 8/7
= 49/7  8/7=
= 57/7
the f(57/7) = 57^2/49 +294/49
=3249/49 + 294/49
= 3543/49
which is not even on the list

algebra  Damon, Sunday, March 16, 2008 at 8:09pm
You are welcome
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