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April 18, 2014

April 18, 2014

Posted by **marilyn** on Sunday, March 16, 2008 at 5:12pm.

- physics -
**Damon**, Sunday, March 16, 2008 at 6:55pmF = G M1 m/r^2 direction attractive

let M1 = 650. the mass of B

then G M1 = 6.67*10^-11 *650

= 4.34* 10^-8

so I will call

k = 4.34*10^-8 and do the arithmetic later

now each force = k m/r^2

now let's do forces in the X direction

no x force from A on B

x force C on B = k(1800/80^2) = -2812 k

x force D on B = k (100/.4^2) = +625 k

total x force Fx = - 2187 k

The only y force is from A in + y direction

Fy = k (100/.5^2) = k 100/.25 = 400 k

so

Fx = -2187(4.34*10^-8)

Fy = + 400 (4.34*10^-8)

You can multiply that out

if magnitude and direction are asked then

F = sqrt(Fx^2+Fy^2)

tan angle to - x axis in quadrant 2 = Fy/|Fx|

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