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November 29, 2014

November 29, 2014

Posted by **jimmy** on Sunday, March 16, 2008 at 3:35pm.

7pq

----

14p(to the power2)q(to the power -2)

also

(5ab)All to the power -2 x 15a (to the power 2) x b (to the power 3)

- math -
**drwls**, Sunday, March 16, 2008 at 3:44pm7 pq/[14p^2*q^-2)]

= (1/2)q^3/p

(Exponents in the denominator can be subtracted from exponents in the numerator, or vice versa, if they are exponents of the same number).

1/q-2 = q^2

(5ab)^-2 * 15a^2b^3 =

15 a^2b^3/[25 a^2 b^2]

=(15/25)b = (3/5)b

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