In the reaction

KNaC4H4O6 + H2O + COCl2 * 6H2O �¨
what r the products?

and is the tartrate ion the catalyst?

To determine the products of a chemical reaction, we need to analyze the reactants and their behavior during the reaction. In the given reaction:

KNaC4H4O6 + H2O + COCl2 * 6H2O →

The reactants are KNaC4H4O6 (potassium sodium tartrate), H2O (water), and COCl2 * 6H2O (phosphorous oxychloride hexahydrate).

To identify the products, we first need to understand the nature of the reactants and how they interact. Potassium sodium tartrate is an organic compound, which can undergo hydrolysis in the presence of water. Hydrolysis is a reaction in which a compound breaks down into its constituent components due to the addition of water.

In this case, the water molecule will react with the tartrate ion (C4H4O6^2-) in KNaC4H4O6, resulting in the formation of free C4H4O6^2- ions and K+ and Na+ ions. Additionally, COCl2 (phosphorous oxychloride) is a reactive compound with water, and when it reacts with water, it forms HCl and H2CO3.

Therefore, the products of the given reaction are:

C4H4O6^2- (tartrate ion)
K+ (potassium ions)
Na+ (sodium ions)
HCl (hydrochloric acid)
H2CO3 (carbonic acid)

Regarding the catalyst, a catalyst is a substance that increases the rate of a chemical reaction without being consumed in the reaction. In the given reaction, tartrate ion (C4H4O6^2-) is not mentioned as a catalyst. Thus, it is not acting as a catalyst in this specific reaction.

Please note that the reaction could also involve other side reactions or unforeseen factors, so further analysis might be necessary for a comprehensive understanding.