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Calculus - Integrals

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Integral of (dt/[sqrt(t)+25tsqrt(t)]}

From 1/75 to 3/25

I'm at a complete loss at what to do.

  • Calculus - Integrals -

    let y = t^(1/2)
    dy = (1/2) t^-(1/2) dt
    dt = 2 t^(1/2) dy = 2 y dy
    sqrt t = y
    25 t sqrt t = 25 y^3
    so
    integral 2 y dy/(y+25 y^3)
    or
    integral of 2 dy/(1 + 25 y^2)

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