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March 6, 2015

March 6, 2015

Posted by **Sean** on Saturday, March 15, 2008 at 9:55pm.

From 1/75 to 3/25

I'm at a complete loss at what to do.

- Calculus - Integrals -
**Damon**, Saturday, March 15, 2008 at 10:41pmlet y = t^(1/2)

dy = (1/2) t^-(1/2) dt

dt = 2 t^(1/2) dy = 2 y dy

sqrt t = y

25 t sqrt t = 25 y^3

so

integral 2 y dy/(y+25 y^3)

or

integral of 2 dy/(1 + 25 y^2)

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