Posted by **Mel** on Saturday, March 15, 2008 at 8:17am.

I am trying to work through the following equations and can't remember how to do them. I would appreciate if someone could show me how to do both questions so I can see the difference.

Find the equation of the line that passes through

A(4,-2) and is parallel to 2x-3y=7

A(-2,5) and is perpendicular to 2x-y=6

- Maths -
**drwls**, Saturday, March 15, 2008 at 8:37am
You should try these your self. There are three steps. Do them both the same way.

Put the equation of the line that you want to be parallel to in the form

y = mx + b

That tells you the slope, m.

For the first equation y = (2/3)x -7/3. Therefore the slope is m = 2/3 for that line.

For the second step, write this equation for a line going through the point (x*, y*):

y - y* = m(x - x*)

I find this form very easy to remember. It is easy to see why y must equal y* when x = x*, forcing the line to go through the point.

Then, if you want, rearrange the equation into standard y = mx + b form.

y = mx + (y*-mx*)

- Maths -
**drwls**, Saturday, March 15, 2008 at 10:30am
That is the correct answer. Good work! Now do the other one

## Answer This Question

## Related Questions

- algebra - could someone check my answers to these few questions? "What is the ...
- Math - Okay .. Im working on Linear Equations and am VERY confused can someone ...
- Algebra ?? - What would be the missing piece of information given the following ...
- Calculus - I am stuck on both of these questions. Would you please tell me if my...
- chem - Use the balanced equation, N2 + O2 --> 2NO, to answer the following ...
- can someone help me with a question of an explanat - my question is for math, I ...
- Cultural Diversity - I am working on an autobiographical research paper that ...
- math - Could someone help me solves these questions? And can you show me how you...
- maths equations - could you please help me on this equation r = sx2/2t im really...
- Math 2 - You should make two selections from the list below. Which two of the ...

More Related Questions