What is the molarity of a solution of 10% by mass cadmium sulfate, CdSO4 (molar mass = 208.46 g/mol) by mass? The density of the solution is 1.10 g/mL.
5.28
To find the molarity of the solution, we need to know the number of moles of the solute (cadmium sulfate, CdSO4) and the volume of the solution.
First, let's calculate the number of moles of CdSO4 in the solution.
To do this, we need to determine the mass of the CdSO4 in the solution. We know that the solution is 10% by mass cadmium sulfate, so we can assume we have 10 grams of CdSO4 for every 100 grams of solution.
Next, we convert the mass of CdSO4 to moles by dividing by its molar mass. The molar mass of CdSO4 is 208.46 g/mol.
Number of moles (n) = mass (m) / molar mass (MM)
n = 10 g / 208.46 g/mol
Now, let's find the volume of the solution. We are given the density of the solution, which is 1.10 g/mL.
To find the volume, we divide the mass of the solution (100 g) by its density.
Volume (V) = mass (m) / density (d)
V = 100 g / 1.10 g/mL
Finally, we can calculate the molarity (M) using the formula:
Molarity (M) = number of moles (n) / volume (V)
M = n / V
Substituting the values we have calculated:
M = (10 g / 208.46 g/mol) / (100 g / 1.10 g/mL)
Now, we can simplify and compute the result.