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December 22, 2014

December 22, 2014

Posted by **Sean** on Friday, March 14, 2008 at 9:00pm.

1) Integral of [2* sqrt((1+cosx)/2)].

All I can see is that I take the 2 out of the integral, and put it out front.

2) Integral of [(sec(x))^4].

Here I'm completely stumped. I'm not sure how to start, either.

I'd really appreciate help on these two problems. They've really got me stuck.

P.S. Also, if anyone could supply a link of math tutorials of some sort, please do!

- Calculus - Integrals -
**Count Iblis**, Friday, March 14, 2008 at 11:11pm1) use the formula:

cos(2x) = 2 cos^2(x) - 1

You can use this formula to derive a formula for cos(1/2 x) in terms of

cos(x). You can then simplify the square root using that formula.

2) sec^4 (x) = 1/cos^4(x)

You can use a reduction formula, which is easier to derive for positive powers of cos,, you just apply that backwards for this case.

Notation cos = c, sin = s:

c^n = c^(n-2)c^2 = c^(n-2)[1-s^2] =

c^(n-2) - c^(n-2)s^2

So the integral of c^n is the integral of c^(n-2) minus the integral of

c^(n-2)s^2. This latter integral can be written up to a minus sign:

Int of c^(n-2)sdc = ( let's do a partial integration) =

Integral of s d[c^(n-1)/(n-1)] =

Integral of d[sc^(n-1)/(n-1)] -

Integral of c^(n-1)/(n-1)ds =

sc^(n-1)/(n-1) -

Integral of c^(n)/(n-1) dx

So, we have expressed the integral of cos^n in terms of the integral of

cos^(n-2), a trignometric function and cos^n again. You can bring that later integral of cos^n back to the other side of this expression and solve for the integral of cos^n in terms of the integral of cos^(n-2).

You can then verify that this equation is also valid for negative n (that's is trivial). So, you can use it to express the integral of 1/c^4 in terms of the integral of 1/c^2, that latter integral is of course, the tan function.

- Calculus - Integrals -
**Sean**, Saturday, March 15, 2008 at 8:20amI don't quite get how you did the first one. Mainly the cos(1/2 x)

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