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October 25, 2014

October 25, 2014

Posted by **Anonymous** on Friday, March 14, 2008 at 11:56am.

I don't know how to solve this problem.

- Discrete Math: Equations of a Line -
**Reiny**, Friday, March 14, 2008 at 3:14pmlet M be the midpoint

then M =(3,1,3/2)

then a direction vector of the line is

[3-0,1+1,3/2-1] = [3,2,1/2] or [6,4,1}

possible parametric equations:

x = 0 + 6t

y = -1 + 4t

z = 1 + t

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