Posted by Anonymous on Friday, March 14, 2008 at 11:56am.
let M be the midpoint
then M =(3,1,3/2)
then a direction vector of the line is
[3-0,1+1,3/2-1] = [3,2,1/2] or [6,4,1}
possible parametric equations:
x = 0 + 6t
y = -1 + 4t
z = 1 + t
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